Set Parent Template Defined Content to Output in Child Template

Question

I have a layout template, we'll call that Template A that is extended by another template, we'll call that Template B that includes another template, we'll call that Template C that includes another template lets call that Template D

So the visually it goes like so:

-Template A

--Template B

---Template C

----Template D

In Template C I define some content such as "Hello World" as well as a bunch of other content.

I do not want Template C to output the "Hello World" content but instead want Template D to decide where it is output as defined in Template C

I'm thinking that somewhere i might should use embed rather than include but i'm a bit hazy on exactly how to achieve this. Any help would be greatly appreciated.

NOTE: The content defined in Template C is defined after Template C includes Template D and also the content that is defined is not just a simple string as indicated above "hello world" but actually much more complex data.

UPDATE: Here is an example of the templates to help better understand the question.

Template C:

{% for block in entry.body.level(1) %}
  {% include 'Template D' %}
  {% if block.children is not empty %}
    {% block child %}
        {% for block in block.children %}
            {% include 'Template E' %}
        {% endfor %}
    {% endblock %}
  {% endif %}
{% endfor %}

Where Template E is the "Hello World" content mentioned above.

Template D:

 {% if block.slide|length %}
     <div class="stuff">
         <ul class="somestuff">
             {% for background in block.slide %}
                 <li style="background-image:url({{ background.url() }})"></li>
             {% endfor %}
         </ul>
     </div>

     <section id="text-slider">
         <div class="container">
             {% block child %}{% endblock %}
        </div>
     </section>
 {% endif %}

And more code also after that endif. Where Block Child (in Template C) is the content to be defined and Block Child (in Template D) is where i want it output.

Answer 1

You could use include...with, as specified in the Twig Docs here

Example for your case:

{# in Template C #}
{% include 'template-d.twig' with {'foo':'Hello World'} %}

This should give Template D access to foo. Hope that helps!

Answer 2

The correct way of doing this for anybody interested is as I had guessed, using embed rather than include but also to setup a recursive macro like so in Template C:

{% macro recursiveBlock(block) %}
  {% import _self as self %}
  {% embed 'Template D' %}
      {% if block.children is not empty %}
          {% block child %}
              {% for block in block.children %}
                  {{ self.recursiveBlock(block) }}
              {% endfor %}
          {% endblock %}
      {% endif %}
  {% endembed %}
{% endmacro %}

{% from _self import recursiveBlock %}

{% for block in entry.body.level(1) %}
    {{ recursiveBlock(block) }}
{% endfor %}

Template D remains unchanged.

While Sam's answer was correct for a much simpler need, this is the way it had to be done (as far as I understand) for something more complex.