3

I need to loop through the 6 latest entries from 3 different structures. The problem is, the entries are located on different levels. One of the structures has entries on level 3, and the other two has entries on level 1.

5

If you explicitly need only the entries at level 3, and those at level 1, I think combining two queries works best:

{# Get ids for all entries from the different structures and levels #}
{% set entriesAtLevelThree = craft.entries.section('level-3-section').level(3).limit(6).ids() %}
{% set entriesAtLevelOne = craft.entries.section(['level-1-section-1', 'level-1-section-2']).level(1).limit(6).ids() %}

{# Combine those IDs #}
{% set entryIdsCombined = entriesAtLevelThree | merge(entriesAtLevelOne) %}

{# Get all entries (so, no IDs this time), using your IDs #}
{% set allEntries = craft.entries.id(entryIdsCombined).limit(6).order('postDate DESC') %}

{% for entry in allEntries %}
    {# do your thing #}
{% endfor %}

You can, of course, cache this by wrapping it in {% cache %} tags.

| improve this answer | |
  • 1
    You should add .limit(6) to the first queries as well, otherwise the entryIdsCombined array could be very large. – gromgull Mar 6 '15 at 9:53
  • 1
    Good point. Will do. – Paul Mar 6 '15 at 9:54

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