How to filter entries by slug in url segment?

Question

I want to return entries in the news section, except the one that has a slug the matches url segment 2.

I've tried:

{% for entry in craft.entries.section('news').slug(not craft.request.getSegment(2)).limit(6) %}...
{% for entry in craft.entries.section('news').slug('and, not craft.request.getSegment(2)').limit(6) %}...

But neither work - all entries are returned.

What's the right syntax please?

Answer 1

I think there is just some confusion between what should be a string or not. From the docs on Parameter Value Syntax:

To exclude entries with a given value, you must pass in a string, prefixed with not

To that end the following should work for your example:

{% for entry in craft.entries.section('news').slug('not ' ~ craft.request.getSegment(2)).limit(6) %}...