Get the URL of a section?

Question

Similar to this question: Output URL to section

Let's say we have a section with handle 'places' which defines its URL format as 'places/{slug}'—how do I get the link to the 'places' index page? The question above goes via the entries in that section but that just gets the url of the first entry in that section.

Answer 1

Here's what I did. You'll need to set sectionId first.

{% set thing = craft.sections.getSectionById(sectionId) %} {{thing.getUrlFormat()|split('/')[0]}}

Answer 2

Expanding a little bit more on Dustin C solution.

It is possible to get the siteURL instead of hard coding it:

<a href="{{ siteUrl }}{{ entry.section.name|kebab }}">{{ entry.section }}</a>

Answer 3

I know this is a year old, but I was scratching around trying to find a solution to this, and I came up with this.

Try the kebab modifier.

<a href="http://example.com/{{ entry.section|kebab }}">{{ entry.section }}</a>

The kebab case makes it possible to convert your section titles to usable links -- at least they did in my case.

Hope this helps someone in the future.

Answer 4

Currently there is no method to get the link to the section's index page. However, if you try to visit http://domain.com/sectionhandle/, it will will try to load a template named index.html inside a folder named after your sectionhandle.

In your example:

http://domain.com/places/ -> templates/**places/index.html

I think that you can easily make that assumption and use that in a link. It's not elegant, and it doesn't take into account locales, but.. It's the only way at the moment, I think.