I'm making a staff page with a User field type, so you select all the users you want displayed. I'm having trouble showing each user's photo though. This works:

{% for user in block.staffList.all() %}
   Image URL: {{ craft.assets.id(user.photoId).one().url }}
{% endfor %}

But seems far from the ideal solution. Is there a more graceful way to do this?

  • Ok, this works: {{ user.photoUrl(user.id) }}, but still seems a little redundant – Bryce Sep 25 at 20:54

It works very simply. Note that the photo field is an asset object, not an array of asset objects.

{% for user in block.staffList.all() %}
   Image URL: {{ user.photo.getUrl() }}
{% endfor %}
| improve this answer | |
  • That's the ticket, thanks! Just a quick note: to skip over people that don't have photos, you can use {% if member.photo is not null %} – Bryce Sep 27 at 17:53
  • @Bryce Of course, you can still do eager loading and caching {% for user in block.staffList.with(['photo']).all() %} . I gave a short answer, Craft CMS has many methods to optimize. – Pavel Pavlovich Sep 28 at 7:29

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.