Bear with me as I am not sure the best way to explain this. But to try and summarise... how can I loop through related entries (locations) inside a a related entries loop (exams -> related to the current entry/page) but ONLY output the locations and ONLY output the unique locations (ie. I don't want it t show location1, location1, location2, location1. I just want it to show location1 and location2 (once - unique). This is where I am at, but not working yet.

Here is a screenshot to try and illstrate: enter image description here

I only want Bushy to appear once, not 4 times.

So my page is setup like this; First I set the Mock Exams to find all the Mock Exams related to the current entry (page). Like so:

{% set mockExams = craft.entries
  targetElement: entry,
  field: 'mockExamCategory'
  .all() %}

I am then using this code to list all the mock exams in 2 separate areas on the page. This works fine and as expected.

However, I need to then get all the unique location entries that are related to the mock exams. I took me ages to fathom this out on how to to do this. I only managed with some great support through the Discord channel.

Anyway, the way this was finally achieved was as follows:

  {% set uniqueLocations = [] %}
  {% set uniqueLocationsIds = [] %}
  {% for entry in mockExams %}
    {% set locations = craft.entries.section('locations').relatedTo(entry.id).all() %}

    {% for location in locations %}
      {% if location.id not in uniqueLocationsIds %}
        {% set uniqueLocationsIds = uniqueLocationsIds|merge([location.id]) %}
        {% set uniqueLocations = uniqueLocations|merge([location]) %}
      {% endif %}
    {% endfor %}
  {% endfor %}

{% for location in uniqueLocations %}
  {{ location.title }}<br />
  {{ location.address }}
{% endfor %}

I have written this up for reference if anyone else comes across this.

But also for anyone more experienced in Craft - is this the most efficient way or is there a more efficient/streamlined approach?

1 Answer 1


How about this?

{% set uniqueLocations = craft.entries.section('locations').relatedTo(mockExams).all() %}

{% for location in uniqueLocations %}
  {{ location.title }}<br />
  {{ location.address }}
{% endfor %}

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.