Paginate Tag Page

Question

I'm looking to paginate my tag page, but unfortuntately it throws a fairly strange error. Remove the pagination -> the page works perfectly? Bit confused, the only thing I think it may be is that it's only returning 1 result so errors?

{% set tag = craft.tags.title(tag).first() %}

{% set users = craft.users.group('influencer').relatedTo(tag).order('userTotalFollowers asc').all() %}

{% if users|length %}

{% paginate users as pageInfo, pageUsers %}
{% for user in users %}
  {{ user.username }}
{% endfor %}


<div class="row justify-content-between">
  <div class="col text-left">
    {% if pageInfo.prevUrl %}<a href="{{ pageInfo.prevUrl }}" class="btn btn-outline-secondary">← Previous</a>{% endif %}
  </div>
  <div class="col text-right">
    {% if pageInfo.nextUrl %}<a href="{{ pageInfo.nextUrl }}" class="btn btn-outline-secondary">Next →</a>{% endif %}
  </div>
</div>
{% endif %}

Argument 1 passed to craft\helpers\Template::paginateCriteria() must implement interface yii\db\QueryInterface, array given, called in /app/storage/runtime/compiled_templates/ef/efb8567b56752c2a98d031bc1d51461f73acc6fdd1f2c8872e44feb2af18359c.php on line 133

Answer 1

With the all() function at the end of your users-definition you get an array of all users.

The pagination expects a QueryInterface. This is logical: With pagination you do not want to load all users, only the ones listed on the page.

In addition, to paginate, you have to limit() your query to a number of entries.

Therefore: {% set users = craft.users.group('influencer').relatedTo(tag).order('userTotalFollowers asc').limit(10) %} should probably work.

You can find more information and an example in the documentation.

I hope this helps and solves the problem.

Answer 2

Try modifying the loop to the following: {% for user in pageUsers %}

Answer 3

All you need to do is add a limit in your user query. This might help you.