2

I've got a for loop working perfect with a limit of 5. Then I throw in the if statement to filter those entries that correspond with a global variable I have set. The problem is the if statement is after the for loop with the limit and only doing it's thing to the 5 entries and not all of the entries.\

I want to use the if statement on all the entries to return the ones I want, then limit it to 5. In another DIV I have and offset(5), so the rest go there. I hope that makes sense.

{% for entry in craft.entries.section('news').order('articleOrder desc').limit(5).find() %}

    {% if entry.currentYear2 == currentEdition.currentYear2 and currentEdition.currentMonth2 in entry.currentMonth2 %}

        <h2>{{ entry.title }}</h2>

        <p>{{ entry.body }}</p>

    {% endif %}

{% endfor %}
1

If I'm following you correct, you can use a conditional in a for loop to do what you want.

So in your case, it would be something like:

{% for entry in craft.entries.section('news').order('articleOrder desc').limit(5).find() if entry.currentYear2 == currentEdition.currentYear2 and currentEdition.currentMonth2 in entry.currentMonth2 %}
   ...
{% endfor %}
  • It's not doing anything different. I have 10 entries total. 6 meet the if statement criteria. When the limit is set at 20, 6 entries are returned. When the limit is set at 5, only 1 entry is returned when I want it to return 5. – afc Mar 23 '17 at 13:16
  • I think the answer you are looking for is in Brads answer here -> craftcms.stackexchange.com/questions/21046/… That takes into account the amount of times a valid entry has been found.... – Gįëł Tėttëłæår Mar 29 '18 at 14:18

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