Timeline for Get children of multiple entries
Current License: CC BY-SA 4.0
2 events
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| Jun 3, 2023 at 8:38 | comment | added | James Smith |
Beware that pretty much every time you write .one() or .all(), you are executing DB queries... and fairly heavy ones in the case of element queries. So I wouldn't recommend this way. You could mitigate slightly by eager loading the children: craft.entries.id(entryID).with('children').one(), but still not great.
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| Jun 1, 2023 at 15:18 | history | answered | Droemmelbert | CC BY-SA 4.0 |